Answer:
[tex]y = 1400 + 5.2x[/tex] --- Running cost
[tex]y = 25 x[/tex] --- Monthly income
71 cars
R1775
Step-by-step explanation:
Given
Expenses
[tex]Salaries = 1400.00[/tex]
[tex]Others = 5.20[/tex] per car
Income
[tex]Rate = 25.00[/tex] per car
Solving (a): Expression for the running cost
This is calculated as:
[tex]y = Salary + Others * x[/tex]
Where
y = Total running cost
x = number of cars
So:
[tex]y = 1400 + 5.20 * x[/tex]
[tex]y = 1400 + 5.2x[/tex]
Solving (b): Expression for monthly income
This is calculated as:
[tex]y = Rate * x[/tex]
Where
y = Total income
x = number of cars
So:
[tex]y = 25.00 * x[/tex]
[tex]y = 25 x[/tex]
Solving (c): Break even
To do this, we equate the expressions in (a) and (b)
[tex]y = y[/tex]
[tex]25x = 1400 + 5.2x[/tex]
Collect Like Terms
[tex]25x -5.2x= 1400[/tex]
[tex]19.8x= 1400[/tex]
Solve for x
[tex]x = \frac{1400}{19.8}[/tex]
[tex]x = 71[/tex]
Solving (d): How much to break even
Substitute 71 for x in any of (a) or (b)
[tex]y = 25 x[/tex]
[tex]y = 25 * 71[/tex]
[tex]y = 1775[/tex]
Solving (e): There is no question to answer on the "graph"