In Triangle ABC, the length of AB is 3 cm, and the length of BC is 7 cm. Triangle ABC will be dilated with the
center at the origin to create Triangle A'B'C'. If the image of Point A(-3,5) after the dilation is A' (-12, 20),
what is the length of B'C'?
A.12 cm
B. 16 cm
C.22 cm
D.28 cm

Respuesta :

Answer:

28 cm

Step-by-step explanation:

dilation means to increase or decrease the shape so find the amount it was dilated by dividing -12 by -3 or 20/5 u should get 4 then multiply 7 by 4.

  Option (D) will be the answer.

Dilation of a point or a figure:

  • If a point (x, y) is dilated by a scale factor 'k' about the origin, image of the point will be defined by the rule,

        (x, y) → (kx, ky)

  • If a figure is dilated by a scale factor 'k', rule for the dilation will be,

         Scale factor = [tex]\frac{\text{Dimension of the image}}{\text{Dimension of the preimage}}[/tex]

Given in the question,

  • ΔABC with AB = 3 cm and BC = 7 cm
  • Point A(-3, 5) of ΔABC is dilated by a scale factor 'k' about the origin to form the image triangle A'B'C' with A'(-12, 20)

Use the rule of dilation of a point about the origin,

(x, y) → (kx, ky)

A(-3, 5) → (-12, 20)

            → [4(-3), 4(5)]

Therefore, scale factor 'k' = 4.

If the side BC is dilated to form the image side B'C' by a scale factor 'k',

Scale factor = [tex]\frac{\text{Dimension of the image}}{\text{Dimension of the preimage}}[/tex]

4 = [tex]\frac{B'C'}{BC}[/tex]

B'C' = 4(BC)

       = 4(7)

       = 28 cm

      Therefore, Option (D) will be the answer.

Learn more about the transformation here,

https://brainly.com/question/2865768?referrer=searchResults