In a combustion reaction, pentane (molar mass (MM) = 72.17 g/mol) burns, in the presence of oxygen (MM = 32.00 g/mol), to produce carbon dioxide (MM = 44.01 g/mol) and water (MM = 18.02 g/mol).

The balanced reaction is shown here: C5H12 (l) + 8 O2 (g) à 5 CO2 (g) + 6 H2O (g)

If 4.0 mol of O2 is available, what is the maximum number of moles of water that can be produced (AKS 4f)?

A.
3.0 mol

B.
4.0 mol

C.
5.0 mol

D.
8.0 mol

E.
2.0 mol

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Eduard22sly Eduard22sly · Answer 1 · 2022-02-24T10:58:52+01:00

The maximum number of mole of water that can be produced is 3 moles (Option A)

C₅H₁₂ + 8O₂ —> 5CO₂ + 6H₂O

From the balanced equation above,

8 moles of O₂ reacted to produce 6 moles of H₂O

From the balanced equation above,

8 moles of O₂ reacted to produce 6 moles of H₂O.

Therefore,

4 moles of O₂ will react to produce = (4 × 6) / 8 = 3 moles of H₂O.

Thus, we can conclude that the maximum mole of water produced is 3 moles

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