1. Find the missing side lengths of the special right triangles. Leave your answers as radicals in simplest form 30° 9

Answer:
a = 18 units
b = 9√3 units
Step-by-step explanation:
By applying sine rule in the given triangle,
sin(30°) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
[tex]\frac{1}{2}=\frac{9}{a}[/tex]
a = 18 units
Now apply cosine rule in the given triangle,
cos(30°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{b}{a}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{b}{18}[/tex]
b = [tex]\frac{18\sqrt{3} }{2}[/tex]
b = [tex]9\sqrt{3}[/tex] units