Answer: The pressure of nitrogen will be 2.0 atm
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 1.0 atm
V = Volume of gas = 10.0 L
n = number of moles = ?
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]297K[/tex]
[tex]n=\frac{PV}{RT}[/tex]
[tex]n=\frac{1.0atm\times 10.0L}{0.0820 L atm/K mol\times 297K}=0.41moles[/tex]
Now again using ideal gas equation :
[tex]P=\frac{nRT}{V}=\frac{0.41mol\times 0.0821Latm/Kmol\times 297K}{5.0L}=2.0atm[/tex]
Thus pressure of nitrogen will be 2.0 atm
