legendninja804
contestada

Two old RSM students were standing 10 feet apart when they spotted Mrs. Rifkin. If
they immediately run in opposite directions at the speeds of 150 feet per minute and
160 feet per minute respectively, how many minutes will pass before they are 1870
feet apart?

Respuesta :

MattF4

Answer:

6

Step-by-step explanation:

Speed = Distance/time

Therefore time must = distance/speed

Since the two students are running apart from eachother, we can add their speeds together.

Also we can subtract 10 feet from our goal of 1870 since they're already 10 feet apart.

1860 feet/(150+1650) feet per minute

We can cancel out the feet since it's a common term.

And we're left with 6 minutes.

okpalawalter8

The  time before they are 1870 feet apart is mathematically given as

X=6min

What is the time before they are 1870 feet apart?

Question Parameters:

Two old RSM students were standing 10 feet apart

at the speeds of 150 feet per minute

they are 1870

feet apart

Generally, the time they are apart is mathematically given as

X=final distance apart/speeds of run

Therefore

X=1870/(150+160)

X=6min

In conclusion,time before they are 1870 feet apart

X=6min

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