Answer:
t = 1 s
Step-by-step explanation:
The function models the height of the ball after t seconds is given by :
[tex]h=32t - 16t^2[/tex]
We need to find how many seconds does it take for the ball to reach its maximum height.
For maximum height put dh/dt = 0
[tex]\dfrac{dh}{dt}=\dfrac{d}{dt}(32t - 16t^2)\\=32-32t[/tex]
So,
32-32t = 0
t = 1
So, it will take 1 second to reach its maximum height.
