If 3 quantities are equally divided in 9 groups, then each group will contain 1/3 of such quantities, which is one-third of one of such considered quantities.
When 'a' is divided by 'b', then the result we get from the division is the part of 'a' that each one of 'b' items will get.
Thus, if 10 mangoes are there, and 2 people, then 10 ÷ 2 is the number of mangoes each person would get, which is 5.
Division, thus, can be interpreted as equally dividing the number that is being divided in total x parts, where x is the number of parts the given number is divided.
Thus, [tex]a \div b[/tex]equal parts.
Also, we can write: [tex]a \div b = a \times \dfrac{1}{b}[/tex]
(it is since a = a times 1 so [tex]a/b = 1 \times (a/b) = (1/b) \times a[/tex] )
Suppose that the question is asking us to find the quantity each group will possess of those 3 quantities which is divided into 9 groups equally (assumingly).
3 quantities to be divided into 9 groups of equal quanties, or say 9 equal parts.
Thus, the quanity each part would get is:
[tex]3 \div 9 = \dfrac{3}{9} = \dfrac{1 \times 3}{3 \times 3} = \dfrac{1}{3} \: \rm quantities[/tex]
1/3 shows one-third of the considered quantity which was available in 3 units and was divided in 9 groups, each having equal amount of that quantity.
Thus, if 3 quantities are equally divided in 9 groups, then each group will contain 1/3 of such quantities, which is one-third of one of such considered quantities.
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