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three raised to the square of a number, x, is equal to nine raised to the power two times the same number x decreased by one.


please help! i will mark brainliest

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Answer:

Step-by-step explanation:

[tex]3^x^2=9^{2x-1}\\3^x^2=(3^2)^{2x-1}\\x^2=4x-2\\x^2-4x+2=0\\X^2-4X+4=-2+4\\(X-2)^2=2\\|x-2|=\pm \sqrt{2} \\x=2+\sqrt{2},2-\sqrt{2}[/tex]

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