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A pistol that fires a signal flare gives it an initial velocity (muzzle velocity) of 173 m/s at an angle of 62.9 ∘ above the horizontal. You can ignore air resistance. Find the flare's maximum height if it is fired on the level salt flats of Utah.

Respuesta :

Answer:

[tex]y_{max} = 1208.8 m[/tex]

Explanation:

As we know that flare is shot at an angle of 62.9 degree

and the initial speed is given as

[tex]v_i = 173 m/s[/tex]

now we have

[tex]v_y = v sin\theta[/tex]

[tex]v_y = 173 sin62.9[/tex]

[tex]v_y = 154 m/s[/tex]

now the maximum height of the flare is given as

[tex]y_{max} = \frac{v^2}{2g}[/tex]

[tex]y_{max} = \frac{154^2}{2(9.81)}[/tex]

[tex]y_{max} = 1208.8 m[/tex]

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