Answer:
(1) First pair; (2, 3), (7, 3), d₁ = 5
(2) Second pair; (-2, 5), (-2, -3), d₂ = 8
(3) Third pair; (-8, 5), (-2, 5), d₃ = 6
(4) Fourth pair; (-9, 1), (6, 1), d₄ = 15
Step-by-step explanation:
Given pair of points;
(1) (2, 3), (7, 3)
(2) (-2, 5), (-2, -3)
(3) (-8, 5), (-2, 5)
(4) ) (-9, 1), (6, 1)
The distance between each pair of points is calculated as follows;
[tex]d = \sqrt{(y_2-y_1)^2 + (x_2-x_1)^2}[/tex]
(1) first pair; (2, 3), (7, 3)
[tex]d_1 = \sqrt{(3-3)^2 + (7-2)^2} \\\\d_1 = 5[/tex]
(2) second pair; (-2, 5), (-2, -3)
[tex]d_2 = \sqrt{(-3-5)^2 + (-2-(-2))^2}\\\\d_2 = \sqrt{(-3-5)^2 + (-2+2)^2} \\\\d_2 = 8[/tex]
(3) Third pair; (-8, 5), (-2, 5)
[tex]d_3 = \sqrt{(5-5)^2 + (-2-(-8))^2}\\\\d_3 = \sqrt{(5-5)^2 + (-2+8)^2} \\\\d_3 = 6[/tex]
(4) Fourth pair; (-9, 1), (6, 1)
[tex]d_4 = \sqrt{(1-1)^2 + (6-(-9))^2}\\\\d_4 = \sqrt{(1-1)^2 + (6+9)^2} \\\\d_4 = 15[/tex]
