Answer:
34176.5 torr
Explanation:
It is given that :
Initial pressure, [tex]$P_1 = 830$[/tex] torr
Initial volume, [tex]$V_1 = 650 \ cm^3$[/tex]
Initial temperature, [tex]$T_1 = 85^\circ C$[/tex]
Final volume, [tex]$V_2 = 65 \ cm^3$[/tex]
Final temperature, [tex]$T_2 = 350^\circ C$[/tex]
Therefore, using the combined gas laws, we can write :
[tex]$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$[/tex]
Substituting the values, we get
[tex]$\frac{830 \times 650}{85}=\frac{P_2\times 65}{350}$[/tex]
[tex]$P_2 = \frac{830 \times 650 \times 350}{85 \times 65}$[/tex]
= 34176.5 torr
So the new pressure is 34176.5 torr.
