Answer:
F = m g / 4, F = 12250 N
Explanation:
For this exercise we must use the rotational equilibrium relation
∑τ = 0
let's set a reference system on the wheel where the bus is turning and that the anti-clockwise rotations have been positive
-2F x_string + W x_bus = 0
x_bus =\frac{l}{2} cos 45
x_string = l cos 45
where F is the force on each wheel and W the weight of the bus ,, we assume that the center of mass is in the middle and x_bus is the perpendicular distance from the center of mass to the turning point.
2F l cos 45 = W [tex]\frac{l}{2}[/tex] cos 45
F = m g / 4
to finish the calculation we must assume a mass for the bus m = 5000 kg
F = 5000 9.8 / 4
F = 12250 N
