Answer:
grams H₂(g) = 6.11 grams H₂(g) used
Explanation:
Convert all given values to moles (if not already in moles), solve by rxn ratios and then convert moles to needed dimensions.
N₂(g) + 3H₂(g) => 2NH₃(g)
excess ? 34.6g/17g/mole = 2.04 moles
moles of H₂(g) needed = 3/2(2.04)moles = 3.05 moles H₂(g)
grams H₂(g) = 3.05 moles x 2 grams/mole = 6.11 grams H₂(g)
