Answer:
12) Line segment AB
[tex]m_{AB} = \frac{7-4}{10-4}= \frac{1}{2}[/tex]
13) Line segment CD
[tex]m_{CD} = \frac{6-11}{15-13}=-\frac{5}{2}[/tex]
14) Line segment EF
[tex]m_{EF} = \frac{7-11}{4-3}= -4[/tex]
15) Line segment GH
[tex]m_{GH} = \frac{5-2}{8-6}= \frac{3}{2}[/tex]
16) Line segment IJ
[tex]m_{IJ} = \frac{0-(-6)}{0-4}=-\frac{3}{2}[/tex]
17) Line segment KL
[tex]m_{KL} = \frac{-2-(-3)}{5-(-2)} = \frac{1}{7}[/tex]
18) Line segment MN
[tex]m_{MN} = \frac{5-5}{3-(-4)} = 0[/tex]
19) Line segment OP
[tex]m_{OP} = \frac{4-(-2)}{13-13} = \frac{1}{0}[/tex]
20) Line segment QR
[tex]m_{QR} = \frac{7-11}{-2-(-7)} = -\frac{4}{5}[/tex]
21) Line segment ST
[tex]m_{ST} = \frac{-2-(-3)}{10-9} = 1[/tex]
Step-by-step explanation:
Coordinates are now described: [tex]A(x,y) = (4,4)[/tex], [tex]B(x,y) = (10, 7)[/tex], [tex]I(x,y) = (-6, 4)[/tex], [tex]J(x,y) = (0,0)[/tex], [tex]Q(x,y) = (-7,11)[/tex], [tex]R(x,y) = (-2,7)[/tex], [tex]C(x,y) = (13,11)[/tex], [tex]D(x,y) = (15, 6)[/tex], [tex]K(x,y) = (-2, -3)[/tex], [tex]L(x,y) = (5,-2)[/tex], [tex]S(x,y) = (9,-3)[/tex], [tex]T(x,y) = (10, -2)[/tex], [tex]E(x,y) = (3, 11)[/tex], [tex]F(x,y) = (4,7)[/tex], [tex]M(x,y) = (-4,5)[/tex], [tex]N(x,y) = (3, 5)[/tex], [tex]G(x,y) = (6,2)[/tex], [tex]H(x,y) = (8,5)[/tex], [tex]O(x,y) = (13,-2)[/tex], [tex]P(x,y) = (13,4)[/tex]
The slope of each line segment is calculated by applying definition of secant line:
12) Line segment AB
[tex]m_{AB} = \frac{7-4}{10-4}= \frac{1}{2}[/tex]
13) Line segment CD
[tex]m_{CD} = \frac{6-11}{15-13}=-\frac{5}{2}[/tex]
14) Line segment EF
[tex]m_{EF} = \frac{7-11}{4-3}= -4[/tex]
15) Line segment GH
[tex]m_{GH} = \frac{5-2}{8-6}= \frac{3}{2}[/tex]
16) Line segment IJ
[tex]m_{IJ} = \frac{0-(-6)}{0-4}=-\frac{3}{2}[/tex]
17) Line segment KL
[tex]m_{KL} = \frac{-2-(-3)}{5-(-2)} = \frac{1}{7}[/tex]
18) Line segment MN
[tex]m_{MN} = \frac{5-5}{3-(-4)} = 0[/tex]
19) Line segment OP
[tex]m_{OP} = \frac{4-(-2)}{13-13} = \frac{1}{0}[/tex]
20) Line segment QR
[tex]m_{QR} = \frac{7-11}{-2-(-7)} = -\frac{4}{5}[/tex]
21) Line segment ST
[tex]m_{ST} = \frac{-2-(-3)}{10-9} = 1[/tex]
