Answer:
[tex]a=2.14\ m/s^2[/tex]
Explanation:
Force in upward direction = 45 N
Force in right side = 60 N
Mass of the object, m = 35 kg
Net force on the object is given by :
[tex]F=\sqrt{45^2+60^2} \\F=75\ N[/tex]
We know that,
F = ma
Where
a is acceleration of the object
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{75\ N}{35\ kg}\\\\a=2.14\ m/s^2[/tex]
So, the acceleration of the object is [tex]2.14\ m/s^2[/tex].
