John needs a plumber to repair the kitchen drain. The plumber charges $85 for the parts that he will need for the repair plus $30 for each hour worked. The maximum amount of money john can spend is $250. Which inequality would represent this situation if x is the number of hours worked?

Respuesta :

Answer:

[tex]30x+85y\leq 250[/tex]

Step-by-step explanation:

Cost of each part is [tex]\$85[/tex]

Cost of working one hour is [tex]\$30[/tex]

Let number of hours worked be [tex]x[/tex] and

number of parts bought be [tex]y[/tex].

The maximum amount of money that John can spend is [tex]\$250[/tex].

From the question we have

[tex]30x+85y\leq 250[/tex]

The required inequality is [tex]30x+85y\leq 250[/tex].