Which pair of equations can be used to solve for x in PQR?

Answer:
A
Step-by-step explanation:
sin57° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{PQ}{PR}[/tex] = [tex]\frac{x}{18}[/tex]
∠ P = 180° - (90 + 57)° ← sum of angles in triangle
∠ P = 180° - 147° = 33° , then
cos33° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{PQ}{PR}[/tex] = [tex]\frac{x}{18}[/tex]
Thus the 2 ratios used to solve for x are A