Answer: The probability that Jenny gets to choose lunch =[tex]\frac{7}{11}[/tex]
Step-by-step explanation:
Choosing any color flower from the bouquet makes events mutually exclusive.
Now, the total number of flowers in the bouquet= 4+3+4 = 11
Number of rose=4
Probability of choosing a rose P(R)=[tex]\frac{4}{11}[/tex]
Number of carnations=3
Probability of choosing a carnation P(C)=[tex]\frac{3}{11}[/tex]
The probability of choosing a rose or a carnation
P(R or C)=P(R)+P(C)=[tex]\frac{4}{11}+\frac{3}{11}=\frac{7}{11}[/tex]
Thus, the probability that Jenny gets to choose lunch =[tex]\frac{7}{11}[/tex]
