Answer:
0.01 Ω
Explanation:
Given that the output voltage varies by 5 mV when loaded from 0.01 A to 1 A
Therefore, the regulators output resistance is given by :
[tex]$I_L=\frac{V_L}{R_L}$[/tex]
[tex]$(1.00 - 0.01)A= \frac{5 \ mV}{R_L}$[/tex]
[tex]$0.99 \ A= \frac{5 \ mV}{R_L}$[/tex]
∴ The line and load regulation is 0.01 Ω