Answer:
[tex]v=\dfrac{\pi}{2}\ ft/s[/tex]
Step-by-step explanation:
Given that,
A wheel with radius 1 foot makes 1 revolution in 4 seconds
We need to find the linera velocity of a point on the edge of the wheel. We know that, the linear velcity is given by :
[tex]v=r\omega[/tex]
Where
[tex]\omega[/tex] is angular velcocity,[tex]\omega=2\pi\ rad[/tex]
[tex]\omega=\dfrac{1}{4}\times 2\pi\\\\=0.5\pi\ rad/s[/tex]
So
[tex]v=1\times 0.5\pi\\\\v=\dfrac{\pi}{2}\ ft/s[/tex]
So, the linear velocity of the wheel is equal to [tex]\dfrac{\pi}{2}\ ft/s[/tex].
