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if 23.1g of O2 occupies a volume of 5.0L at a particular temperature and pressure, what volume will 2.50g of Oxygen gas occupy under the same conditions?

Respuesta :

maacastrobr

Answer:

0.54 L

Explanation:

First we convert the given masses of O₂ into moles, using its molar mass:

  • 23.1 g ÷ 32 g/mol = 0.722 mol
  • 2.50 g ÷ 32 g/mol = 0.078 mol

Then we can solve the problem using Avogadro's law, which states:

  • V₁n₂=V₂n₁

Where:

  • V₁ = 5.0 L
  • n₂ = 0.078 mol
  • V₂ = ?
  • n₁ = 0.722 mol

We input the data:

  • 5.0 L * 0.078 mol = V₂ * 0.722 mol

And solve for V₂:

  • V₂ = 0.54 L

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