Answer:
The mechanical energy of the ball is 112.667 J
Explanation:
Mechanical energy = kinetic energy + potential energy
Where:
kinetic energy = [tex]\frac{1}{2}[/tex]m[tex]v^{2}[/tex]
potential energy = mgh
So that for the given ball, its mechanical energy = [tex]\frac{1}{2}[/tex]m[tex]v^{2}[/tex] + mgh
= m([tex]\frac{1}{2}[/tex][tex]v^{2}[/tex] + gh)
But, m = 400 g = 0.4 kg, v = 23.0 m/s, g = 9.81 m/[tex]s^{2}[/tex] and h = 1.75 m.
Mechanical energy of the ball = 0.4([tex]\frac{1}{2}[/tex]([tex]23^{2}[/tex]) + 1.75*9.81)
= 0.4(264.5 + 17.1675)
= 0.4 x 281.6675
= 112.667
The mechanical energy of the ball is 112.667 J.
