Answer:
See Below.
Step-by-step explanation:
We are given that PQRS is a parallelogram, where X and Y are points on the diagonal QS such that SX = QY.
And we want to prove that quadrilateral PXRY is a parallelogram.
Since PQRS is a parallelogram, its diagonals bisect each other. Let the center point be K. In other words:
[tex]SK=QK\text{ and } PK = RK[/tex]
SK is the sum of SX and XK. Likewise, QK is the sum of QY and YK:
[tex]SK=SX+XK\text{ and } QK=QY+YK[/tex]
Since SK = QK:
[tex]SX+XK=QY+YK[/tex]
And since we are given that SX = QY:
[tex]XK=YK[/tex]
So we now have:
[tex]XK=YK\text{ and } PK=RK[/tex]
Since XY bisects RP and RP bisects XY, PXRY is a parallelogram.