contestada

If I have 21 moles of gas held at a pressure of 780 kPa and a temperature
of 900 K, what is the volume of the gas? PV=nRT R=8.314 L*kPa/mol*K*
PLS HELP!!

Respuesta :

zcathy

Answer:

2.0 x 10^-2 L

Explanation:

PV=nRT

Substitute values into the ideal gas equation.

P = 780 kPa

V = ?

n = 21 mol

R = 8.314 L-kPa/mol-K

T = 900 K

(780 kPa)(V) = (21 mol)(8.314 L-kPa/mol-K)(900 K)

V = (21 mol)(8.314 L-kPa/mol-K)(900K) / (780 kPa)

V = 201.4561...

Round to sig figs.

V = 2.0 x 10^2 L