Answer:
See explanation
Explanation:
Oxidation half equation;
3Cd(s) + 6OH^-(aq) ------> 3Cd(OH)2(s) + 6e
Reduction half equation;
2MnO4^-(aq) + 8H^-(aq) + 6e --------> 2MnO2(s) + 4H2O(l)
Balanced reaction equation;
3Cd(s) + 6OH^-(aq) + 2MnO4^-(aq) + 8H^-(aq) ------> 3Cd(OH)2(s) + 2MnO2(s)
Number of electrons transferred = 6