Brainliest for correct answer

Answer:
1/2
Step-by-step explanation:
Scale factor = (new figure measurement)/(original figure measurement)
Find IP using pythagorus
IP²=(y[tex]_{I}[/tex]-y[tex]_{P}[/tex])²+(x[tex]_{I}[/tex]-x[tex]_{P}[/tex])²
IP²=(4-(-4))²+(4-2)²
IP²=8²+2²
IP²=68
IP=[tex]\sqrt{68}[/tex]
Find I'P' using pythagorus
I'P'²=(y[tex]_{I'}[/tex]-y[tex]_{P'}[/tex])²+(x[tex]_{I'}[/tex]-x[tex]_{P'}[/tex])²
I'P'²=(2-(-2))²+(2-1)²
I'P'²=4²+1²
I'P'²=17
I'P'=[tex]\sqrt{17}[/tex]
Scale factor = (new figure measurement)/(original figure measurement)
=[tex]\sqrt{17}[/tex]/[tex]\sqrt{68}[/tex]
=1/2