Find the area of the following figure: 11in 10in

Answer:
(no simplification) = 55 + (25[tex]\pi[/tex]/2) in^2
(with simplification) = (110 + 25[tex]\pi[/tex])/2 in^2
(with pi rounded to 3.14) = 94.25 in^2
Step-by-step explanation:
Let's start with the easier shape, the triangle. The formula for area of a triangle is 1/2(base)(height). Since at the far right we have 10 in, we can apply that to the triangle to get the base = 10 inches. The height is given as 11 inches so we can then calculate the area which is 55 in^2.
Then, the circle. We know that area of a whole circle = [tex]\pi r^{2}[/tex]. Since we know that a semicircle is 1/2 of a full circle, we can find the area of the entire circle then divide it by 2.
It gives the diameter as 10, divide that by 2 to get the radius. r=5. Plug 5 into the equation of [tex]\pi r^{2}[/tex] and you get 25[tex]\pi[/tex]. Divide that by 2 to get 25[tex]\pi[/tex]/2.
Add the triangle and the semicircle areas.
(no simplification) = 55 + (25[tex]\pi[/tex]/2) in^2
(with simplification) = (110 + 25[tex]\pi[/tex])/2 in^2
(with pi rounded to 3.14) = 94.25 in^2