Answer: The concentration of [tex]I_2[/tex] at equilibrium is 0.45 M
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]
For the given chemical reaction:
[tex]H_2(g)+I_2(g)\rightarrow 2HI(g)[/tex]
The expression for [tex]K_c[/tex] is written as:
[tex]K_c=\frac{[HI]^2}{[H_2]^1[I_2]^1}[/tex]
[tex]6.0=\frac{(0.90)^2}{(0.30)^1\times (I_2)^1}[/tex]
[tex][I_2]=0.45M[/tex]
Thus concentration of [tex]I_2[/tex] at equilibrium is 0.45 M