A container at equilibrium contains the following concentrations: [Hz] - 0.30 M and [HI]
0.90 M. The equilibrium constant is equal to 6.0. What is the concentration of I2 at
equilibrium?
Hzig) + 1218 = 2 Hle)

Respuesta :

Answer: The concentration of [tex]I_2[/tex] at equilibrium is 0.45 M

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]  

For the given chemical reaction:

[tex]H_2(g)+I_2(g)\rightarrow 2HI(g)[/tex]

The expression for [tex]K_c[/tex] is written as:

[tex]K_c=\frac{[HI]^2}{[H_2]^1[I_2]^1}[/tex]

[tex]6.0=\frac{(0.90)^2}{(0.30)^1\times (I_2)^1}[/tex]

[tex][I_2]=0.45M[/tex]  

Thus concentration of [tex]I_2[/tex] at equilibrium is 0.45 M