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A 1-kg ball is 12 m above the ground, with an initial velocity = 0 m/s.

Use the following formulas
[ KE = 1/2 xm x V2]
[P.E = mxgxh] . g =9.8 m/s2
[ Mechanical energy = K.E + P.E]

A 1kg ball is 12 m above the ground with an initial velocity 0 ms Use the following formulas KE 12 xm x V2 PE mxgxh g 98 ms2 Mechanical energy KE PE class=

Respuesta :

Answer:

M = 117.6 J

Explanation:

Given that,

The mass of a ball, m = 1kg

The height of the ball, h = 12 m

At point A, its initial velocity, v = 0

The mechanical energy is the sum of kinetic and potential energy such that,

[tex]M=\dfrac{1}{2}mv^2+mgh\\\\M=0+mgh\\\\M=1\times 9.8\times 12\\\\M=117.6\ J[/tex]

So, the mechanical energy is equal to 117.6  J.

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