Using Cramer’s Rule, the value of x is 0
How to determine the value of x?
We have:
2/5X + 1/4Y = 9/20
2/3X + 5/12 = 3/4
Represent as a matrix
[tex]\left[\begin{array}{cc}2/5&1/4\\2/3&5/12\end{array}\right] \left[\begin{array}{c}9/20&3/4\end{array}\right][/tex]
Start by calculating the determinant of the matrix
A = 2/4 * 5/12 - 2/3 * 1/4
Evaluate the product
A = 5/24 - 1/6
Evaluate the difference
A = (5 - 4)/24
|A| = 1/24
Next, replace the last column with the first
[tex]\left[\begin{array}{cc}9/20&1/4\\3/4&5/12\end{array}\right][/tex]
Calculate the determinant
|x| = 9/20 * 5/12 - 1/4 * 3/4
Evaluate the product
|x| = 3/16 - 3/16
Evaluate the difference
|x| = 0
The value of x is then calculated as:
x = |x|/|A|
So, we have:
x = 0/(1/24)
Evaluate
x = 0
Hence, the value of x is 0
Read more about Cramer's rule at:
https://brainly.com/question/11198799
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