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PLEASE HELP I LITERALLY CAN'T
What volume does 1 mol of Ar(g) occupy at 25 C and 100 kPa?
a) 24.8 L
b) 1.0 L
c) 22.4 L
d) 40.0 L

What volume is occupied by 1 mol of Cl2(g) at SATP?
a) 12.4 L
b) 11.2 L
c) 22.4 L
d) 24.8 L

Respuesta :

I think the answer is B for 1. And D for 2.

The amount of volume will be (1) 23.10 L and ( 2) 22.4 L by using gas law.

What is gas law?

Gas law gave the relation between pressure, volume and temperature.

It can be expressed as:

PV = nRT.

where, P is pressure, R is gas constant and T is temperature.

Calculation of volume by using gas law.

1) Given data:

n = 1 mol

T = 25 degree C = 25 + 273 =

P = 100 kpa

Volume can be determined by the gas law.

PV = nRT

V = nRT/P

V = 1 × 8.31 × 278 / 100

V = 23.10 L

2) It is known that at STP 1 mol of any gas volume will be 22.4 L.

Therefore, the correct answer will be option (c).

To know more about gas law.

https://brainly.com/question/12669509

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