Answer:
[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} \ \\ y & {14} & {13} & {12} & {11} & {10} \ \\ A & {14} & {26} & {36} & {44} & {50}\ \end{array}[/tex]
Step-by-step explanation:
Given
[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} \ \\ y & {14} & {13} & {12} & {11} & {10} \ \\ A & { } & { } & { } & { } & {50}\ \end{array}[/tex]
Required
Complete the table of Areas
Using the complete column:
Where x = 5, y = 10 and A = 50,
We can deduce that, the area is calculated as:
[tex]A = 5 * 10 = 50[/tex]
i.e.
[tex]A = x * y[/tex]
So, for other values of x and y, the area is calculated as thus:
[tex]x = 1; y = 14[/tex]
[tex]A = 1 * 14 = 14[/tex]
[tex]x = 2; y = 13[/tex]
[tex]A = 2 * 13 = 26[/tex]
[tex]x = 3; y=12[/tex]
[tex]A = 3 * 12 = 36[/tex]
[tex]x =4;y =11[/tex]
[tex]A = 4 * 11 = 44[/tex]
So, the complete table is:
[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} \ \\ y & {14} & {13} & {12} & {11} & {10} \ \\ A & {14} & {26} & {36} & {44} & {50}\ \end{array}[/tex]
