Respuesta :
Answer:
E. 0.9953
Step-by-step explanation:
The computation of the p value is shown below:
According to the question
The participant choosen from 3 different state parks, r = 3
And there are 3 different age group, s = 3
So, degrees of freedom is
= (r-1) × (s-1)
= 2 × 2
= 4
And, the Test statistic is 15.01
Now
p-value = P(Chisq < 15.01 )
= 0.9953
In the chisquare table see the degree of freedom i.e. 4
Answer:
0.0047
Step-by-step explanation:
This is what college board says
The value 0.0047 is the probability that χ2 is greater than 15.01 in an χ2 distribution with (3−1)(3−1)=4 degrees of freedom.