Write the mostValuableNeighbor method, which compares the item in row r and column c to the items to its left and to its right. The method determines which of the three items has the greatest value and returns its name. If more than one of the values have a value that is greatest, then any of their names can be returned. If the item has no item to its left, it is compared only to the item to its right. If the item has no item to its right, it is compared only to the item to its left.

The following method is written in Java, using the Item class and ItemGrid class found online we can use this method to grab the 2-dimensional array and compare the three neighbors in the same row. It saves the position of the neighbor with the greatest value in the variable greatest and then uses that position to call the getName() method from the object in that position to get the name of that Neighbor and returns the name.

public String mostValuableNeighbor(ItemGrid grid, int r, int c) {

int greatest = grid[r][c];

if (grid[r][c+1].getValue() > greatest.getValue()) {

greatest = grid[r][c+1];

}

if (grid[r][c-1].getValue() > greatest.getValue()) {

greatest = grid[r][c-1];

}

return greatest.getName();

}

lhmarianateixeira lhmarianateixeira · Answer 2 · 2022-03-03T11:59:32+01:00

In this exercise we have to use the knowledge of computational language in JAVA to write the code.

We have the code in the attached image.

The code in Java can be found as:

public String mostValuableNeighbor(ItemGrid grid, int r, int c) {

int greatest = grid[r][c];

if (grid[r][c+1].getValue() > greatest.getValue()) {

greatest = grid[r][c+1];

}

if (grid[r][c-1].getValue() > greatest.getValue()) {

greatest = grid[r][c-1];

}

return greatest.getName();

}

See more about JAVA at brainly.com/question/26104476