Respuesta :

Answer:

350.7 g of NaCl

Explanation:

For this reactions our reactants are:

HCl and Na₂CO₃.

Then, the reaction is:

2HCl + Na₂CO₃ →  2NaCl  +  H₂CO₃

2 moles of hydrochloric acid react to 1 mol of sodium carbonate in order to produce 2 moles of salt and 1 mol of carbonic acid.

Ratio is 1:2. 1 mol of sodium carbonate can produce 2 moles of NaCl

Then, 3 moles of carbonate may produce (3 . 2) /1 = 6

We convert the moles to mass to determine the theoretical yield

6 mol . 58.45g /mol = 350.7 g

The theoretical yield of NaCl produced is 350.7 g.

What is NaCl?

NaCl is a salt, and it is an ionic compound.

The reaction is

[tex]\rm 2HCl + Na_2CO_3 \rightarrow 2NaCl + H_2CO_3[/tex]

2 mol of HCl reacts with 1 mol of [tex]Na_2CO_3[/tex] and produces 2 mol of NaCl and 1 mol of [tex]H_2CO_3[/tex].

The ratio will be [tex]Na_2CO_3[/tex] : NaCl

                                1 : 2

Then, for 3 mol of [tex]Na_2CO_3[/tex]

[tex]\dfrac{3 \times 2}{1} = 6[/tex]

Now, convert the moles to mass

[tex]6\; mol \times 58.45g /mol = 350.7 g[/tex]

Thus, the theoretical yield produced is 350.7 g.

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