Respuesta :
Answer:
350.7 g of NaCl
Explanation:
For this reactions our reactants are:
HCl and Na₂CO₃.
Then, the reaction is:
2HCl + Na₂CO₃ → 2NaCl + H₂CO₃
2 moles of hydrochloric acid react to 1 mol of sodium carbonate in order to produce 2 moles of salt and 1 mol of carbonic acid.
Ratio is 1:2. 1 mol of sodium carbonate can produce 2 moles of NaCl
Then, 3 moles of carbonate may produce (3 . 2) /1 = 6
We convert the moles to mass to determine the theoretical yield
6 mol . 58.45g /mol = 350.7 g
The theoretical yield of NaCl produced is 350.7 g.
What is NaCl?
NaCl is a salt, and it is an ionic compound.
The reaction is
[tex]\rm 2HCl + Na_2CO_3 \rightarrow 2NaCl + H_2CO_3[/tex]
2 mol of HCl reacts with 1 mol of [tex]Na_2CO_3[/tex] and produces 2 mol of NaCl and 1 mol of [tex]H_2CO_3[/tex].
The ratio will be [tex]Na_2CO_3[/tex] : NaCl
1 : 2
Then, for 3 mol of [tex]Na_2CO_3[/tex]
[tex]\dfrac{3 \times 2}{1} = 6[/tex]
Now, convert the moles to mass
[tex]6\; mol \times 58.45g /mol = 350.7 g[/tex]
Thus, the theoretical yield produced is 350.7 g.
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