Answer:
[tex]\frac{25}{56}[/tex] pounds
Step-by-step explanation:
By using unitary method,
∵ 1 full tub of water weighs = [tex]3\frac{1}{8}[/tex] pounds
∴ [tex]\frac{1}{7}[/tex] of a water tub will weigh = [tex]3\frac{1}{8}\times \frac{1}{7}[/tex]
= [tex]\frac{(24+1)}{8}\times \frac{1}{7}[/tex]
= [tex]\frac{25}{56}[/tex] pounds
Therefore, water filled in [tex]\frac{1}{7}[/tex]th part of the tub will weigh [tex]\frac{25}{56}[/tex] pounds.
The weight of the tub if filled up to 1/7 full is 25/56 pounds
Given:
If filled halfway:
= 1/7 × 3 1/8
= 1/7 × 25/8
= (1 × 25) / (7 × 8)
= 25/56 pounds
Therefore, the weight of the tub if filled to 1/7 of the capacity is 25/56 pounds
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