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1. A sample of gas was compressed at 35 °C from a volume of 300.0 mL to a volume
of 100.0 mL where its pressure was found to be 30.0 mm Hg. What was the original
pressure of the gas, if there was no change in temperature? Type in your numerical
answer in the textbox. You may type in your work or upload a picture of it using the
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Respuesta :

maacastrobr

Answer:

10 mm Hg

Explanation:

We can solve this problem using Boyle's law, which states that at a constant temperature:

  • P₁V₁=P₂V₂

The subscript 1 stands for the initial conditions and 2 for the final conditions.

In this case:

  • P₁ = ?
  • V₁ = 300.0 mL
  • P₂ = 30.0 mm Hg
  • V₂ = 100.0 mL

We input the data:

  • P₁ * 300.0 mL = 30.0 mm Hg * 100.0 mL

And solve for P₁:

  • P₁ = 10 mm Hg

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