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What volume, in milliliters, of water is needed to make an 8.40 M solution of HCl acid using 180. grams of HCI ?
0 603 mL
O 41.4 mL
0 587 ml
0 24.1 mL

Respuesta :

maacastrobr

Answer:

0 587 mL

Explanation:

First we convert 180 grams of HCl into moles, using its molar mass:

  • 180 g ÷ 36.46 g/mol = 4.94 mol HCl

Now we can use the number of moles and the given concentration to calculate the required volume, applying the definition of molarity:

  • Molarity = moles / liters
  • Liters = Moles / molarity
  • 4.94 mol / 8.40 M = 0.588 L

Finally we convert liters into milliliters:

  • 0.588 L * 1000 = 588 mL

The closest answer is option C, 587 mL.

mahima6824soni

The volume needed to make an 8.40 M solution of HCl is 0.587 ml.

The correct option is C.

What is HCl?

HCl is a strong acid. It is present in our stomach to help in digesting food.

Step1: covert 180 grams into moles

Molar mass of HCl is 36.46 g

[tex]\dfrac{180 g}{36.46 g/mol } = 4.94\; mol\; HCl[/tex]

Step2: calculate the molarity

[tex]\rm Molality = \dfrac{mol}{L}\\\\\rm L = \dfrac{4.94 mol }{8.40 M} = 0.588 L\\[/tex]

Covert the liters into ml

[tex]\dfrac{0.588 L}{1000} = 588 mL[/tex]

Thus, the volume of the solution is 588 ml., nearest is option C, 587 ml.

Learn more about HCl

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