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What volume of DI water, in mL, must you use to dissolve 30.0 g of NaOH in order to make a 1.25 M solution? mL (round to whole number)

Respuesta :

samueladesida43

Answer:

600mL

Explanation:

Molarity of a solution (M) = number of moles (n) ÷ volume (V)

number of moles = mass/molar mass

Molar mass of NaOH = 23 + 16 + 1

= 40g/mol

mole = 30/40

n of NaOH = 0.75mol

Using Molarity = n/V

V = number of moles ÷ molarity

V = 0.75 ÷ 1.25

V = 0.6L

In milliliters (mL), the volume of NaOH will be 0.6 × 1000

= 600mL

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