Answer:
h = 16x
Step-by-step explanation:
The volume of a sphere and a cone is same such that,
[tex]V_s=V_c\\\\\dfrac{4}{3}\pi r^3=\dfrac{1}{3}\pi R^2h[/tex]
We have, r = x, R = (1/2)x, h= ? (height of the cone)
So,
[tex]\dfrac{4}{3}\pi x^3=\dfrac{1}{3}\pi (\dfrac{x}{2})^2h\\\\4x^3=\dfrac{x^2}{4}h\\\\h=\dfrac{16x^3}{x^2}\\\\h=16x[/tex]
So, the height of the cone is equal to 16x.