Answer:
f = 270.37 Hz
Explanation:
Given that,
The length of the long open end air column, L = 63.8 cm
The speed of sound in the air is 345 m/s
We need to find the frequency of the air column. For an open pipe, the frequency is given by :
[tex]f=\dfrac{nv}{2L}\\\\f=\dfrac{345}{2\times 63.8\times 10^{-2}}\\\\f=270.37\ Hz[/tex]
So, the frequency of the air column is equal to 270.37 Hz.