Answer:
The magnitude of the force is 79.893 N.
Explanation:
The magnitude of the electrostatic force between the two particles is determined by Coloumb's Law, whose formula is:
[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex] (1)
Where:
[tex]\kappa[/tex] - Electrostatic constant, in newtons-square meters per square coulomb.
[tex]q_{A}, q_{B}[/tex] - Electric charges, in coulombs.
[tex]r[/tex] - Distance, in meters.
If we know that [tex]\kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]q_{A} = +40\times 10^{-6}\, C[/tex], [tex]q_{B} = - 80\times 10^{-6}\, C[/tex] and [tex]r = 0.6\,m[/tex], then the magnitude of the force is:
[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex]
[tex]F = 79.893\,N[/tex]
The magnitude of the force is 79.893 N.
