Answer:
1) They are not inverses
2) They are inverses
Step-by-step explanation:
We need to find the composition function between these functions to verify if these functions are inverses. If f[g(x)] and g[f(x)] are equal to x they are inverses.
1)
Let's find f[g(x)] and simplify.
[tex]f[g(x)]=\frac{1}{2}g(x)+\frac{3}{2}[/tex]
[tex]f[g(x)]=\frac{1}{2}(4-\frac{3}{2}x)+\frac{3}{2}[/tex]
[tex]f[g(x)]=\frac{7}{2}-\frac{3}{4}x[/tex]
As f[g(x)] is not equal to x, these functions are not inverses.
2)
Let's find f[g(x)] and simplify.
[tex]f[g(n)]=\frac{-16+(4n+16)}{4}[/tex]
[tex]f[g(n)]=\frac{-16+4n+16}{4}[/tex]
[tex]f[g(n)]=\frac{4n}{4}[/tex]
[tex]f[g(n)]=n[/tex]
Now, we need to find the other composition function g[f(x)]
Let's find g[f(x)] and simplify.
[tex]g[f(x)]=4(\frac{-16+n}{4})+16[/tex]
[tex]g[f(x)]=-16+n+16[/tex]
[tex]g[f(x)]=n[/tex]
Therefore, as f[g(n)] = g[f(n)] = n, both functions are inverses.
I hope it helps you!
