Answer: [tex](1,-5)[/tex]
Step-by-step explanation:
Given
Curve is
[tex]y=x^2-2x-4[/tex]
At the turning point of the curve, the slope will be zero.
Differentiate the curve
[tex]\Rightarrow y'=2x-2[/tex]
Substitute 0 for [tex]y'[/tex]
[tex]\Rightarrow 2x-2=0\\\Rightarrow x=1[/tex]
[tex]\therefore y=1^2-2\times 1-4=-5[/tex]
[tex](1,-5)[/tex] is the turning point
