Step-by-step explanation:
Let x be the diagonal distance,
by pythagoras' theorem,
[tex] {c}^{2} = {a}^{2} + {b}^{2} [/tex]
where c is the diagonal
a and b are the 2nd and 3rd longest side, interchangeable.
given a = 50m, b = 25m,
[tex] {c}^{2} = {50}^{2} + {25}^{2} \\ {c}^{2} = 2500 + 625 \\ {c}^{2} = 3125 \\ c = \sqrt{3125} \\ = 55.9m \: (nearest \: tenth)[/tex]
