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A heater has a resistance of 15 Ω. It operates on 120 V. What thermal energy is supplied by the heater in 2 minutes?

Respuesta :

Answer:

E = 115.2 kJ

Explanation:

Given that,

Resistance, R = 15 ohms

Voltage, V = 120 V

We need to find the energy supplies by the heater in 2 minutes or 120 s.

The formula for the thermal energy supplies is given by :

[tex]E=I^2Rt[/tex]

We know that, V = IR

So,

[tex]E=\dfrac{V^2t}{R}\\\\E=\dfrac{(120)^2\times 120}{15}\\\\E=115200\ J\\\\E=115.2\ kJ[/tex]

So, 115.2 kJ of energy is supplied.