9514 1404 393
Answer:
(v -7)/(5v^2)
Step-by-step explanation:
Cancel common factors from numerator and denominator.
[tex]\dfrac{v^2-49}{20v^3}\times\dfrac{4v^2-24v}{v^2+v-42}=\dfrac{4}{20}\cdot\dfrac{(v-7)(v+7)(v)(v-6)}{v^3(v+7)(v-6)}\\\\=\dfrac{1}{5}\cdot\dfrac{v-7}{v^2}\cdot\dfrac{v(v+7)(v-6)}{v(v+7)(v-6)}=\boxed{\dfrac{v-7}{5v^2}}[/tex]
