Answer:
1279
Explanation:
We have the mean u = 1497
Standard deviation sd = 322
We find the x distribution using 25%
P(Z<z) = 0.25
Z = -0.675
From here we use the formula for z score
X = z(sd) + u
X = -0.675*322 + 1497
X = -217.35 + 1497
X = 1279.6
Which is approximately 1279
So we conclude that the maximum sat scores in year 2014that meets with the requirements of this course is 1279