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in 1910, halley's comet traveled close to earth about 1/7 of the distance from the earth to the sun. Earth's distance from the sun is 149.6 million kilometers. ( if u answer all them i'll give u brainliest but if not its alr)

1. How close was halley's comet to earth in 1910?create an equation to answer the question.

2. estimate the next 3 years when halley's comet will appear.

3. the core of halley's comet is oblong in shape, with its longest dimension 16 km long. earth's diameter is about 12,700 km . how many times larger in diameter is earth than halley's comet?

Respuesta :

francocanacari

1) In 1910, Halley's Comet was 21.37 million kilometers close to Earth.

2) Given that Halley's Comet orbits the sun at about 75 years, and that the last time it passed near the Earth was in 1986, the years in which it will happen again will be 2061, 2136 and 2211.

3) Earth is 794 times larger in diameter than Halley's Comet.

Since in 1910, Halley's Comet traveled close to Earth about 1/7 of the distance from the Earth to the Sun, and Earth's distance from the Sun is 149.6 million kilometers, to determine 1) how close was Halley's Comet to Earth in 1910, 2) estimate the next 3 years when Halley's Comet will appear, and 3) if the core of Halley's Comet is oblong in shape, with its longest dimension 16 km long, and Earth's diameter is about 12,700 km, how many times larger in diameter is Earth than Halley's Comet, the following calculations must be performed:

1)

  • 149.6 / 7 = X
  • 21.37 = X

2)

  • 1986 + 75 = 2061
  • 2061 + 75 = 2136
  • 2136 + 75 = 2211

3)

  • 12700/16 = X
  • 793.75 = X

Learn more about maths in https://brainly.com/question/26088658

MrRoyal

The relationship between Halley's comet and the earth is an illustration of proportions

The given parameters are:

  • Earth's distance from the sun = 149.6 million kilometers
  • Halley's comet traveled close to 1/7 of the distance.

(a) The distance

The distance which Halley's comet get to is calculated using:

[tex]d = \frac 17 \times 149.6\ million\ km[/tex]

So, we have:

[tex]d = 21.37\ million\ km[/tex]

Hence, Halley's comet was 21.37 million kilometers close to the earth in 1910.

(b) The next three years it will appear

From the complete question, the comet is visible every 74 years.

It appears in 1910.

So, the next three years are:

[tex]Year\ 1 = 1910 + 74 = 1984[/tex]

[tex]Year\ 2 = 1984 + 74 = 2058[/tex]

[tex]Year\ 3 = 2058 + 74 = 2132[/tex]

Hence, the comet will appear in 1984, 2058 and 2132.

(c) The number of times the earth is larger

The diameter of the earth is given as: 12700 km, while the longest dimension of the oblong shaped comet is 16 km.

So, the number of times (n) which the earth is greater than the comet is:

[tex]n = \frac{12700}{16}[/tex]

[tex]n = 794[/tex] --- approximated

Hence, the diameter of the earth is 794 times larger than Halley's Comet.

Read more about proportion at:

https://brainly.com/question/1781657

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